450.0 88.7889
451.0 88.7889
452.0 88.7889
453.0 88.7889
454.0 88.7889
455.0 88.7889
456.0 88.7889
457.0 88.7889
458.0 88.7889
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460.0 88.7889
461.0 88.7889
462.0 88.7889
463.0 88.7889
464.0 88.7888
465.0 88.7888
466.0 88.7888
467.0 88.7888
468.0 88.7888
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471.0 88.7888
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473.0 88.7888
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475.0 88.7888
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477.0 88.7887
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486.0 88.7886
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492.0 88.7885
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501.0 88.7883
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505.0 88.7882
506.0 88.7882
507.0 88.7882
508.0 88.7882
509.0 88.7881
510.0 88.7881
511.0 88.7881
512.0 88.7880
513.0 88.7880
514.0 88.7880
515.0 88.7879
516.0 88.7879
517.0 88.7879
518.0 88.7878
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520.0 88.7877
521.0 88.7877
522.0 88.7877
523.0 88.7876
524.0 88.7876
525.0 88.7875
526.0 88.7875
527.0 88.7874
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531.0 88.7872
532.0 88.7872
533.0 88.7871
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535.0 88.7870
536.0 88.7870
537.0 88.7869
538.0 88.7868
539.0 88.7868
540.0 88.7867
541.0 88.7866
542.0 88.7866
543.0 88.7865
544.0 88.7864
545.0 88.7864
546.0 88.7863
547.0 88.7862
548.0 88.7862
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550.0 88.7860
551.0 88.7859
552.0 88.7858
553.0 88.7858
554.0 88.7857
555.0 88.7856 其实这里确实忽略了薄膜另一个面的反射,因为在这个膜厚内薄膜的另一面反射几乎为0,换句话说可以把这层膜看做无限厚的膜,而透射率则随厚度的增加成指数的衰减,在这里状况下,薄膜内部的多光束干涉的影响可以忽略不计,如果楼主一定要算,计算量就更大了,但结果还是这个,偶可以肯定。如果你要求反射位相,只要看ρs=-0.9147+0.2262i,所以反射位相变化tg-1(0.2262/-0.9147)=166.10度 应该说TFC程序代码中可能有一套更为完备的计算公式把膜厚的变化也考虑在内。 500 nm 处的位相厚度是:kndcosQ,k=2*3.14/500,cosQ是复折射角的的余弦,要用到一元二次方程辅助求解,而等效导纳的计算中要用到位相角度的tan值,我想知道金属复位相的tan的求法.介质的我会求 可以算的和TFC一模一样.但K不能忽略的情况我有点问题.
当金属薄膜镀得很薄是,干涉现象很明显,即使不这样,在长波段的R值开始与短波段的值有较大的区别. 看应用薄膜光学第67至71页,计算量太大,自己算吧,好不。 你们真牛 我现在还不会使用TFC有 使用说明书么 麻烦给我发一份贝(中文的)我邮箱dw19811111@163.com
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