[求助]如何用jones矩阵求解折叠腔中输入光与输出光的关系
<p><br/><font size="4"><font face="Times New Roman">C1</font>为对基波有δ<font face="Times New Roman">1</font>单程相位延迟的倍频晶体（如<font face="Times New Roman">KTP</font>），<font face="Times New Roman">C2</font>为对基波有δ<font face="Times New Roman">2</font>单程相位延迟的增益晶体（如<font face="Times New Roman">Nd</font>：<font face="Times New Roman">YAG</font>），<font face="Times New Roman">m1</font>、<font face="Times New Roman">m2</font>为端面反射镜，<font face="Times New Roman">OC</font>为折叠镜（也是腔的输出耦合镜）。<font face="Times New Roman">S</font>、<font face="Times New Roman">P</font>为光波在<font face="Times New Roman">OC</font>上的两个偏振轴，分别处于系统的子午面和弧矢面内，<font face="Times New Roman">f </font>、<font face="Times New Roman">s</font>为晶体的快、慢轴。设<font face="Times New Roman">S</font>和<font face="Times New Roman">C1</font>快轴之间的夹角为φ，和<font face="Times New Roman">C2</font>快轴之间的夹角为ψ，假设输入光的偏振方向与<font face="Times New Roman">x</font>轴平行，所以输入光的<font face="Times New Roman">Jones</font>矩阵为A1*=<shapetype><font face="Times New Roman"><stroke joinstyle="miter"></stroke><formulas><f eqn="if lineDrawn pixelLineWidth 0"></f><f eqn="sum @0 1 0"></f><f eqn="sum 0 0 @1"></f><f eqn="prod @2 1 2"></f><f eqn="prod @3 21600 pixelWidth"></f><f eqn="prod @3 21600 pixelHeight"></f><f eqn="sum @0 0 1"></f><f eqn="prod @6 1 2"></f><f eqn="prod @7 21600 pixelWidth"></f><f eqn="sum @8 21600 0"></f><f eqn="prod @7 21600 pixelHeight"></f><f eqn="sum @10 21600 0"></f></formulas><path connecttype="rect" extrusionok="f" gradientshapeok="t"></path><lock vext="edit" aspectratio="t"></lock><lock></lock></font></shapetype><shape><imagedata></imagedata></shape>，则输出光与输入光的关系为A2=M×A1，其中，</font></p><p></p><p>这个矩阵哪儿出错了，请高手指教，万分感谢！！！</p>
页:
[1]